Re Organize array by content value

Yuval S.
Tel Aviv,

Dec 27, 2018
10 Posts

0 ✔  |  ✗ 0  

Re: Re Organize array by content value

Hi,

need help...

I have an array of 10 numbers
Arr = {2,9,5,7,8,4,1,0,6,3}

i want to re organize the array by content value:
Arr = {0,1,2,3,4,5,6,7,8,9,}

Is there a command that will make this process short instead of using a for loops ?

Thanks !

Solution Available
Yuval S.
Tel Aviv,

Dec 27, 2018
10 Posts

1 ✔  |  ✗ 0  

Re: Re Organize array by content value

Arr = {2,9,5,7,8,4,1,0,6,3}

    Print "This the Array:\r\n"
        
    for i = 0 to (VarDimSize(Arr)-1)
    print (str(Arr[i]))
    next

    for j = 1 to (VarDimSize(Arr)-1)
        for i=0 to (VarDimSize(Arr)-2)
            if Arr[i] > Arr[i+1] then
                Temp = Arr[i]
                Arr[i] = Arr[i+1]
                Arr[i+1] = Temp

            EndIf


        Next

    Next

    Print "This is the Array after sort:\r\n"

    for i = 0 to (VarDimSize(Arr)-1)
    print (str(Arr[i]))
    next


I succeded to do this with two for loops.



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